Refer to the table of indices of refraction if necessary. Determine the angle of refraction of the light ray upon entering the crown glass and upon leaving the crown glass. Using this conceptual criterion as a check of your answer can often identify incorrect solutions to problems.Įxample Problem B A ray of light in air is approaching the boundary with a layer of crown glass at an angle of 42.0 degrees. And indeed it is - 36.2 degrees (theta r) is smaller than 52.0 degrees (theta i). Thus, the angle of refraction should be smaller than the angle of refraction. In this problem, the light ray is traveling from a less optically dense or fast medium (air) into a more optically dense or slow medium (water), and so the light ray should refract towards the normal - FST. When finished, it is always a wise idea to apply the FST and SFA principles as a check of your numerical answer. Proper algebra yields the answer of 36.2 degrees for the angle of refraction. Now list the relevant equation (Snell's Law), substitute known values into the equation, and perform the proper algebraic steps to solve for the unknown. N r = 1.333 (from table) Θ i = 52 degrees
The solution to this problem begins like any problem: a diagram is constructed to assist in the visualization of the physical situation, the known values are listed, and the unknown value (desired quantity) is identified.
Determine the angle of refraction of the light ray. In this part of Lesson 2, we will investigate several of the types of problems that you will have to solve, and learn the task of tracing the refracted ray if given the incident ray and the indices of refraction.Įxample Problem A A ray of light in air is approaching the boundary with water at an angle of 52 degrees. If any three of the four variables in the equation are known, the fourth variable can be predicted if appropriate problem-solving skills are employed. N r = index of refraction of the refractive mediumĪs with any equation in physics, the Snell's Law equation is valued for its predictive ability. N i = index of refraction of the incident medium Where Θ i ("theta i") = angle of incidence The equation is known as the Snell's Law equation and is expressed as follows. We fold about 1 inch of the paper to the left, crease, then bring it back slightly, open the paper and press down the paper to form the squash fold.In a previous part of Lesson 2, we learned about a mathematical equation relating the two angles (angles of incidence and refraction) and the indices of refraction of the two materials on each side of the boundary. Origami Squash Fold Example 5: Finally, this was from an easy origami polar bear. Here we fold the top flap over to the center crease, then pry open the paper and press it down to form the squash fold. Origami Squash Fold Example 4: This is a great example from the origami star box. Notice that this is not a symmetrical squash fold. Bring right side to the center crease, pry open the paper then squash it down. Here we start off with a triangle or diaper fold. Squash Fold Example 3: This was from an easy origami frog. Bring the top flap over, pry open paper and flatten to make a squash fold. Origami Squash Fold Example 2: This was from making a waterbomb base. Bring flap from right to left, open it slightly, press and flatten. Pry open the paper then squash or flatten it down.įlip paper over. We fold the large triangle in half, then bring the flap back to the right. Squash Fold Example 1: This is an example from making a square base. What is a squash fold? Basically, it is when you pry open the paper slightly, then press and flatten the paper to make the fold.īelow are pictures of squash folds that for some of the origami models on this site. This fold before and just didn't know that it's called a squash fold.
#3d rectangle with medium squish. how to#
Maybe you don't know how to make a squash fold or there's a good chance that you've already made
The Origami Squash Fold is a very common fold and you'll hear it mentioned many times in this site.
0 kommentar(er)
